-
-
private void button1_Click(object sender, EventArgs e)
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{
-
-
using (OpenFileDialog dialog = new OpenFileDialog())
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{
-
-
dialog.Multiselect = false;
-
-
if (dialog.ShowDialog() == DialogResult.OK)
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{
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try
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{
-
-
this.textBox1.Text = dialog.FileName;
-
}
-
catch (Exception ex)
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{
-
-
throw (ex);
-
}
-
}
-
}
-
}
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-
-
private void button3_Click(object sender, EventArgs e)
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{
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this.Close();
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}
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-
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private void button2_Click(object sender, EventArgs e)
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{
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FileStream fs = new FileStream(textBox1.Text, FileMode.Open);
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BinaryReader br = new BinaryReader(fs);
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Byte[] byData = br.ReadBytes((int)fs.Length);
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fs.Close();
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string conn = "server=.;database=testDB;Uid=sa;Pwd=sa ";
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SqlConnection myconn = new SqlConnection(conn);
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myconn.Open();
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string str = "insert into pro_table (pro_name,pro_file) values('测试文件',@file)";
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SqlCommand mycomm = new SqlCommand(str, myconn);
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mycomm.Parameters.Add("@file", SqlDbType.Binary, byData.Length);
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mycomm.Parameters["@file"].Value = byData;
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mycomm.ExecuteNonQuery();
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myconn.Close();
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}
-
-
-
private void button4_Click(object sender, EventArgs e)
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{
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string conn = "server=.;database=testDB;Uid=sa;Pwd=sa ";
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string str = "select pro_file from pro_table where pro_name='测试文件' ";
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SqlConnection myconn = new SqlConnection(conn);
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SqlDataAdapter sda = new SqlDataAdapter(str, conn);
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DataSet myds = new DataSet();
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myconn.Open();
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sda.Fill(myds);
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myconn.Close();
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Byte[] Files = (Byte[])myds.Tables[0].Rows[0]["pro_file"];
-
BinaryWriter bw = new BinaryWriter(File.Open("D:\\2.rdlc",FileMode.OpenOrCreate));
-
bw.Write(Files);
-
bw.Close();
-
-
}
这个是项目中解决把报表rdlc存入数据库后再次读出还原出来的方法(经过测试 对任何文件都有效[音频文件,压缩包,word文档等])
这里可能有人会问rdlc是xml的为什么不直接操作XML的存储呢?主要是我们项目中rdlc中可能有带有图片的rdlc格式 所以索性就直接二进制流化处理了。
(责任编辑:wendafang) |